Modify the rain program in L isting 10.7 so that it does the calculations using pointers instead of subscripts. (You still have to declare and initialize the array.)
10.7
Listing 10.7 The rain.c Program /* rain.c — finds yearly totals, yearly average, and monthly average for several years of rainfall data */ #include <stdio.h> #define MONTHS 12 // number of months in a year #define YEARS 5 // number of years of data int main(void) { // initializing rainfall data for 2010 – 2014 const float rain[YEARS][MONTHS] = { {4.3,4.3,4.3,3.0,2.0,1.2,0.2,0.2,0.4,2.4,3.5,6.6}, {8.5,8.2,1.2,1.6,2.4,0.0,5.2,0.9,0.3,0.9,1.4,7.3}, {9.1,8.5,6.7,4.3,2.1,0.8,0.2,0.2,1.1,2.3,6.1,8.4}, {7.2,9.9,8.4,3.3,1.2,0.8,0.4,0.0,0.6,1.7,4.3,6.2}, {7.6,5.6,3.8,2.8,3.8,0.2,0.0,0.0,0.0,1.3,2.6,5.2} }; int year, month; float subtot, total; printf(” YEAR RAINFALL (inches)n”); for (year = 0, total = 0; year < YEARS; year++) { // for each year, sum rainfall for each month for (month = 0, subtot = 0; month < MONTHS; month++) subtot += rain[year][month]; printf(“%5d %15.1fn”, 2010 + year, subtot); total += subtot; // total for all years } printf(“nThe yearly average is %.1f inches.nn”, total/YEARS); printf(“MONTHLY AVERAGES:nn”); printf(” Jan Feb Mar Apr May Jun Jul Aug Sep Oct “); printf(” Nov Decn”); for (month = 0; month < MONTHS; month++) { // for each month, sum rainfall over years for (year = 0, subtot =0; year < YEARS; year++) subtot += rain[year][month]; printf(“%4.1f “, subtot/YEARS); } printf(“n”); return 0; }
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